Raman Archith - Microsoft Python Certification Exam 98-281 & PCEP –Preparation Guide: Introduction To Programming Using Python, PCEP – Certified Entry Level Python Programmer
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- Book:Microsoft Python Certification Exam 98-281 & PCEP –Preparation Guide: Introduction To Programming Using Python, PCEP – Certified Entry Level Python Programmer
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- This exam guide prepares a student to get a Microsoft certification Exam-98-281 Introduction to programming using Python.
- This exam guide also prepares the student to get a PCEP Certified entry level Python Programmer, awarded by the Python institute.
- This guide assumes certain level of programming knowledge. It is not a beginner text book.
- Basic programming language skills using Python with hands on experience
- Total Questions: 40
- Total Duration: 45 minutes
- Python certification: 98-381 Introduction to programming using python
- Minimum Pass score: 70%
- Link to details : https://www.microsoft.com/en-us/learning/exam-98-381.aspx
- Syllabus Link : https://www.microsoft.com/en-us/learning/course.aspx?cid=55264
- Module 1: Perform Operations Using Data Types and Operators (20 25%)
- Module 2: Control Flow with Decisions & Loops (25-30%)
- Module 3: Perform input/output operations using console & Files Code (20-25%)
- Module 4: Document & Structure Code, Error/Exceptions, Module/Tools (20-25%)
- Module 5: Python Certification Microsoft 98-381 Full Practice Test #1
- Module 6: Python Certification Microsoft 98-381 Full Practice Test #2
- Evaluate an expression to identify the data type Python will assign to each variable
- Identify str, int, float, and bool data types
- Convert from one data type to another type; construct data structures; perform indexing and slicing operations
- Assignment; Comparison; Logical; Arithmetic; Identity (is); Containment (in)
- Assignment; Comparison; Logical; Arithmetic; Identity (is); Containment (in)
- Assignment; Comparison; Logical; Arithmetic; Identity (is); Containment (in)
Module Questions | Answer & Explanation |
M1Q1 | Answer: 2. Output Value of a is : False Value of b is : 1 First 2 lines assign values to variables a and b using the assignment operator. Line 3: There are 2 operators used, Lne4:First one is python comparison operator ==. It compares values of a and b and returns a boolean result. In this case a == b evaluates to be False. Hence value of False is assigned to a. So the output of this program is : Value of a is : False Value of b is : 1 |
M1Q2 | Answer: 5. m will get the value of 5. Since there is a conversion of the float to int explicitly for m, m = int(i/2) = int(5.5) = 5. For others, j,k,l all will be evaluated as float and will get a value of 5.5 |
M1Q3 | Answer: 1, 3. Statement 3 & Statement 4 will give errors. Arithmetic operators like multiplication, division is not allowed when using strings. However, Statement 1, Statement 2 are correct. the output for those will be : s1=ab and s2 = ac Since string addition is an allowed operation. |
M1Q4 | Answer: 3. 6 Length of the string without spaces is 5. len(s1.rstrip() ) length = 8 means length of the string with spaces on left is 8. ( Right spaces are trimmed here ) Hence number of spaces on the left is 8-5 = 3. Now len(s1.lstrip() ) = 8 which means all the left spaces are trimmed and length of the string including the right spaces is 8. Hence the number of spaces on the right is 8-5 = 3. So the total number of spaces is : Spaces on left + spaces on right = 3+ 3 = 6 |
M1Q5 | Answer: 3,4 v is true since it has one array element in it and the value of the element is false. So count of v is non zero hence v is true Same with x, x has one element and hence of count is non zero and x is true z has a space element in it. count of z is also one making z as true as well y on the other hand is an empty string so bool of an empty string will result in false. So y is false. |
M1Q6 | Answer: 4 First two lines assign values to variables a and b using the assignment operator. Line 3: There are 2 operators used, First one is python comparison operator == . It compares values of a and b and returns a boolean result. In this case a == b evaluates to be False . Hence value of False is assigned to a. So the output of this program is : Value of a is : False Value of b is : 1 |
M1Q7 | Answer: 1,2,3,4 print (s1[1:2] ) In this statement the string from index 1 is picked which is the second position of the string. S1[1] = e print ( s1[1:-3] ) In this statement, the index is counted from the right most and the character next to the character 3 positions from right is picked which is e print ( s1[1] ) character at position 1 is picked which is again e print ( s1[-4]). In this, the 4th character from the right is picked which is also e |
M1Q8 | Answer: 1, 2 k-= q = 6 + 2j - 6 - 2j = 0.0 + 0.0j. Both real and imaginary parts are zero. k = k - (-q) = 6 +2j - ( 6 + 2j ) = 0.0 + 0.0j both real and imaginary parts are zero. For the other 2 equations the value of K is non zero for both real and imaginary parts. k = 12 + 4j ( for k -=q ) k = 24 + 8j ( for k = k - q - q ) |
M1Q8 | Answer: 4 S1[:n} when n=5 wil assign all characters from the 5th position to the left of the string So a = Hello b will be all characters from 5th position to the right of the string. So b = Welcome Good bye When you add a and b both will give the original string. |
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