BIBLIOGRAPHY
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ANSWERS TO PROBLEMS
CHAPTER 1
(What happens when a is an integer?)
except for the value x = , where the sum equals 1/2. (Why?)
- except for the value x = //2, where the sum equals 1/2;
except for the value x = //2, where the sum equals 0.
- .
- .
Hence
so that
- .
CHAPTER 2
3. By the Cauchy inequality
Now integrate. The sharper estimate is obtained by direct use of the Schwarz inequality.
Use the Schwarz inequality with one function equal to |1 + e in x + + e in k x| | and the other equal to 1.
Use the Schwarz inequality.
Suppose g(x) is orthogonal to all the i (x), and let P n (x) = a n (x) + + a n n (x) be such that
Then || g ||2 + ||P n ||2 < 1/ n , so that || g ||2 = 0, i.e., g( x) 0, since g( x ) is continuous.
- No orthogonal function exists, since if g were such a function and if then 0 = c + c = c0 + c2 = C0 + C3 = , i.e., c = c = c = , which violates Bessels inequality (Sec. 6) unless all the ci are zero; b) No orthogonal function exists, by a similar proof; c) An orthogonal function g exists. In fact, consider the continuous function
- If g = a 00 + + a n n is zero, then
0 = || g ||2 = | a 0|2(0, 0) + + |a n | ( n n ),
i.e., a 0 = a = = a n = 0 [for the definition of (, ), see Prob. 10 and Ch. 2, Sec. 10]; b) A polynomial of degree n has at most n real zeros, unless it vanishes identically.
Use repeated integration by parts.