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Lopez C.P. - Linear Algebra with Mathematica

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Cesar Lopez Perez, 2016. 233 p. ASIN: B01AFO8MAUMathematica is a scientific computing software widely used in the experimental sciences. This book develops Mathematica applications in the field of linear algebra. The topics are illustrated with many examples and exercises solved.
The following topics are covered:
Variables And Functions
Variables
Functions Definition
Recursive Functions
Piecewise Functions
Operations With Functions
Data Types Used In The Definition Of The Functions
Numbers, Operations And Most Common Functions. Numbering Systems
Operations Arithmetic
Functions Predefined Of Integer Argument
Numbering Systems
Rational Numbers
Irrational Numbers
Complex Numbers. More Common Functions
Rounding And Approach Functions
Common Constant Used In Mathematica
Random Numbers
El Package Of Number Theory
Algebraic Expressions, Polynomials, And Interpolation
Functions Common Algebraic Operations
Polynomials
Operations Algebraic With Polynomials
Polynomial Interpolation
El Package Numericalmath Approximations
Polynomial Adjustment
Equations And Systems
Resolution Of Equations
Special Commands To Solve Equations
Numerical Methods For Resolution Of Equations
Systems Of Equations
Matrix Algebra
Vectors
Operations With Vectors
Matrices
Operations With Matrices
Special Operations With Matrices
Matrix Decomposition
Range Of A Matrix
Vector Spaces And Linear Applications. Linear Systems
Linear Independence. Bases. Change Of Basis
Linear Applications
Quadratic Forms
Systems Of Linear Equations
Rouche -Frobenius Theorem
Homogeneous Systems

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LINEAR ALGEBRA WITHMATHEMATICACSARPREZ LPEZ
INDEX
Chapter 1. VARIABLES And functions

1.1 VARIABLES
InMathematica, variables are declared via the following syntax: x= a, assigns the value "a" to the variable x.Set[x, a], assigns the value a the variable x.x= y = a, assigns the value "a" to the variables x and at the sametime.{x,y} = {a1, a2}, assigns different values to x and y at the same time.{x,y} = {y, x}, exchanges the values of x and yClear[x] (or x =.), deletes the value assigned to x For example, we can define the variable x and assign itthe value 6 in the following way: In[1]: = x = 6Out[1] = 6 Equivalentto the above syntax would be as follows: In [2]: =Set [x, 6]Out [2] =6
1.2 Functions Definition
Mathematicaoffers the possibility to define custom functions using the following syntax: f[x_]: = expression: defines the function f for single variable xg[x_, y_]: = expression: define function g in the variables x and y.Thegeneral form of a function definition is:f[variable1_, variable2_,...]: = expressionclear[f]:clears the function f. Let'ssee how to define the function f (x) = x ^ 3. In[1]: = f [x_]: = x ^ 3 Nowwe calculate the values f (a+1), f (4) and f(3x+x^2). In[2]:=f[a+1]Out[2]=(1+a)In[3]:=f[4]Out[3]=64In[4]:=f[3x+x^2]2 3Out[4]:=(3 x + x )
1.3 Recursive Functions
Recursivedefinitions of functions you can use in Mathematica. For example, to define thefunction factorial of as follows: In[18]:=fact[1]=1;In[19]:=fact[n_]:=n*fact[n-1] Tocalculate the factorial of 40, we will use the following syntax: In[20]: = fact [5]Out[20] = 120 Alsois you can set recursive functions on the basis of n values above and accordingto n initial conditions. For example: In[1]: = f [x_]: = f [x] = f [x - 1] + f [x - 2]In[2]: = f [0] = f [1] = 1Out[2] = 1 Tocalculate f (5) we use: In [3]: =f [5]Out [3] =8
1.4 Piecewise Functions
Piecewisefunctions tend to be defined in different ways for different intervals ofvariation in the independent variable.

Mathematica enables correct work withthis type of functions, which are defined, in the majority of cases, relying onthe conditional commands, as If, Which, etc. In Mathematica functions suchflooring defined cablul especially operator condicuionla If using adoptsthe following syntax: If[condition, expression1, expression2] Whenthe condition is true evaluates expression1, and when false expression2 isevaluated. As an application example we define the function: In[12]:=Delta[x_] := If [x==0, 1, 0] Thisfunction is set to 1 if x = 0 and in any other case, 0. Wethen define the following function: In[13]: = f [x_]: = If [x > 0, 1, 0] Thisfunction takes the value 1 for all x greater than 0, and takes the value 0 forall x less than or equal to 0. Tographically represent this function, we propose: In[14]:=Plot [f[x], {x, -1, 1}, Axes->{0, 0.5}]Out [14] =see Figure 2.1Figure 21 Whenit is necessary to control the function rather than across a - photo 1 Figure 2.1 Whenit is necessary to control the function, rather than across a single condition,but of several, is available the operator condicuional Wich with thefollowing syntax: Which[condition1, expression1,..., conditionn, expressionn] Ifthe conditioni is true the expressioni is evaluated (i=1, 2, ,n).Putting True as the last condition, gets evaluate the last expression if noneof the previous conditions have been certain. Asan example we consider the piecewise-defined function look: In[15]:=g[x_]:=Which[-2<=x<=2,x^2, -3<=-3, 0, 2<=x, 0, True,x^2] Thefunction g to pieces at intervals is defined (- , - 3) (- 3, - 2), (- 2.2), (2.3), (3, ). Wecan graphically represent the function g as follows: In[16]: = Plot [g [x], {x, - 4, 4}]Out[16] = see Figure 2.2Figure 22 Alsowe can graphically represent the function for the function g - photo 2 Figure 2.2 Alsowe can graphically represent the function for the function g as follows: In[16]:=Plot[g'[x], {x, -4, 4}] Wewill now define a function, called rect, which is set to 1 in the interval[-1/3, 1/3] and which is worth $ 0 in the rest of the real line. In[23]:=rect[x_] := 1 /. (-1/3 <= x && x <= 1/3)In[24]:=rect[x_] := 0 /. (-1/3 <= x && x <= 1/3)In[24]:=rect[x_] := 0 /.

Abs[x] > 1/3 Thisfunction can also be written in the following way: In[22]:= Clear[rect];In[23]:= rect[x_ /. (-1/3 <= x && x >= 1/3)] := 1In[24]:= rect[x_ /. Abs[x] > 1/3] := 0

1.5 Operations WITH functions
UtilizaeMathematica the following functional operators: InverseFunction[f] inverse of the function f.Composition[f, g,...] Composed of f, g,...Identity identity function.Identity[expr] applies the function identity to expr.Nest[f, x, n] applies the function f on x, n times.NestList[f, x, n] generates the list {x, f [x], f [f [x]]... ntimes].Operate[f [x] p] calculates p [f] [x]Operate[p, f [x], n] applies the operator p in f n times. Asexamples we have the following: In[1]:=InverseFunction[ArcSin]Out[1]=SinIn[2]:=f[x_]:= x^2+xIn[3]:=g[x]:= x^3+1In[4]:=Composition[f,g][x]Out[4:=1+x^3+(1+x^3)^2In[5]:=Composition[g,f][x-1]Out[5]=1+(-1+(-1+x)^2+x)^3In[6]:=Composition[f,Sin][x]Out[5] = [x] + Sin [x] ^ 2In[9]:=Clear[f,g]In[1]:=Nest[f,x, 4]Out[1]=f[f[f[f[x]]]]In[2]:=NestList[f, x, 4]Out[2]={x, f[x], f[f[x]], f[f[f[x]]], f[f[f[f[x]]]]}In[18]:=t = ((1 + a)(1 + b))[x]Out[18]= ((1 + a) (1 + b))[x]In[20]:=Operate[p, t]Out[20]=p[(1 + a) (1 + b)][x]
1.6 DATA Types used in the definition of the functions
Wealready know that in Mathematica there is no need to declare the type of thevariables or functions, as in C or FORTRAN. Mathematica manipulates data moreas the APL programming language: deducing the type of data based on how you areusing. Each expression that defines a function is composed of objects in one ormore of the following atomic types: Integer, Real, Rational, Complex, Symbol,and String.

The following table gives an example of each of these indivisibletypes and their descriptions Type description example----------------------------------------------------------------------------------------------------------Integer integer number 3Real real number in the way nn.mm 3.4Rational rational number a/b, a and b integers 3/4Complex complex number of the form a + bI 3 + 4.2 ISymbol value represented by a symbol PiString a string "red"Exercise1. Define the functions f (x) = x ^ 2, g (x) = x ^(1/2) and h (x) = x + Sin(x). Calculate f(2), g(4), h(pi/2), f(a-b^2) and ((x+h) - f (x) f) / hIn[1]:=clear[f, g, h]In[1]:=f[x_]= x^2Out[1]=xIn[2]:=g[x_]= Sqrt[x]Out[2]=Sqrt[x]In[3]:=h[x_]= x+Sin[x]In[4]:=f[2]Out[4]=4In[5]:=g[4]Out[5]=2In[6]:=h[Pi/2]Out[6]=1 + Pi/2In[7]:=f[a-b^2]2 2Out[7]=(a- b )In[8]:=(f[x+h]-f[x])/h2 2- x + (h + x)Out[8]=---------------------------hExercise2. Given the function h defined by:h(x,y) = (cos(x^2-y^2),sin(x^2-y^2))

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